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Techniques

How do I multiply two-digit numbers in my head?

Multiplying two two-digit numbers in your head feels hard only because people try to picture the paper algorithm. Break the problem into easy pieces instead, multiply each piece, and add. The arithmetic is never harder than a single-digit times a two-digit number.

There are a few framings of the same idea; pick the one that fits the numbers. With short daily practice the partial products start coming for free. SIXTY raises difficulty as you get faster and replays the products you miss so the hard pairs get extra reps.

How does the break-apart (distributive) method work?

Split the second number into its tens and ones, multiply the first number by each part, then add the two results. Each multiplication is a manageable single-digit-by-two-digit step.

For 23 × 47: 23 × 40 = 920 and 23 × 7 = 161, then 920 + 161 = 1081. Keep the larger partial product in mind first so the running total is easy to finish.

  1. Split the second number into tens and ones.
  2. Multiply the first number by the tens part.
  3. Multiply the first number by the ones part.
  4. Add the two partial products.

What is the cross method for two-digit multiplication?

The cross method builds the answer from three pieces: tens times tens, the cross of tens and ones, and ones times ones. It mirrors how the digits combine and keeps each piece small.

For 32 × 24: tens × tens is 30 × 20 = 600; the cross is 30 × 4 + 2 × 20 = 120 + 40 = 160; ones × ones is 2 × 4 = 8. Add them: 600 + 160 + 8 = 768.

  1. Multiply the tens of both numbers.
  2. Multiply each number's tens by the other's ones and add those two products (the cross).
  3. Multiply the ones of both numbers.
  4. Add all three results.

When should I use rounding and compensation?

If one number is just below a round value, round it up, multiply, then subtract the extra copies you added. This works best when a number ends in 8 or 9.

For 19 × 7: round 19 up to 20, multiply 20 × 7 = 140, then subtract one 7 because 20 is one more than 19, giving 140 − 7 = 133. For 49 × 6: 50 × 6 = 300, subtract 6 to get 294.

  1. Round one factor up to the nearest 10 and note how many you added.
  2. Multiply the rounded factor by the other number.
  3. Subtract that many copies of the other number.

How do I square a two-digit number quickly?

Squaring is just the break-apart method applied to a number times itself, and rounding to a nearby 10 often makes it cleaner. Use the difference-of-squares shortcut when the number is close to a 10.

For 23 × 23: 23 × 20 = 460 and 23 × 3 = 69, then 460 + 69 = 529. Near a round number, 48 × 48 can be done as 50 × 46 + 2 × 2 = 2300 + 4 = 2304.

Which method should I reach for?

Use break-apart as your default; it always works and the steps are predictable. Switch to rounding and compensation when a factor ends in 8 or 9, and lean on the cross method once the partial products feel automatic.

For a clean case like 23 × 47 break-apart wins, while 19 × 7 is faster as 20 × 7 − 7 = 133. Choosing well is a skill that sharpens with reps, so let practice decide rather than forcing one method on every problem.

Reading is review. Recall is what sticks.

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